{staticvoidMain(string[]args){strings="12345";for(inti=0;i<s.Length;i++){if(i==s.Length-1){Console.Write(s[i]);continue;}Console.Write(s[i]+"");}Console....

include<stdio.h>main(){inti=12345;//输入想要进行操作的整数intj=0inta[]for(j=0;i!=0;j++){a[j]=i%10;i/=10;}for(;j>=0;j--){printf("%1d\n",a[j]...

include<stdio.h>intmain(){intn;scanf("%d",&n);while(n){printf("%d",n%10);n/=10;}printf("\n");return0;}另外一种程序方法：include<stdio.h>intmain(void){int,i,a[5...

1、将12345选中，然后点击“插入→数字”命令，在弹出的“数字”对话框“数字类型”栏里选择中文数字版式“壹、贰、叁?????”单击“确定”，则12345就变成中文数字“壹万贰仟叁佰肆拾伍”。输入"元".2、将12345选中...

include<stdio.h>intmain(void){charnum[1024]={0};gets_s(num,1024);//若不支持c11,请替换为gets(num);for(inti=0;num[i]!='\0';++i)printf("%c",num[i])...

usingnamespacestd;intmain(){intoriginal,key,result=0;cout<<"PleaseEntertheNumber:"<<endl;cin>>original;do{key=original%10;if(key==0){cout<<"NewNumberis0"<

dims(5)fori=0to5s(I)=inputbox("请输入字符串:","提示","12345")s(i)=strreverse(s(i))nextmsgboxjoin(s,vbcrlf)

for(inti=0;i<n;i++){cout<<nums[i];}cout<<endl;return0;}比如输入12345670输出就是12345670。这样不需要考虑数字太多导致组合成的数字溢出的情况。

写入为12345。读的格式应是fscanf(fp,"%1d%1d%1d%1d%1d",&a,&b,&c,&d,&e);后者若用%d,a就读了12345.我们可以用字符串输入流来模拟读数据：include<stdio.h>main(){chars1[]="12345";ch...

main(){inta[5],i,j,t,l;printf("请输入一个5位数:");scanf("%d",&i);a[0]=i/10000;a[1]=(i%10000)/1000;a[2]=(i%1000)/100;a[3]=(i%100)/10;a[4]=i%10;for(l=1;l<5;l++){t=a[0...