发布网友 发布时间:2022-04-28 22:17
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热心网友 时间:2023-09-18 14:08
lim x->inf ((x-k)/(x+k))^x = lim x->inf (1-2k/(x+k))^x 当k=0时,lim x->inf ((x-k)/(x+k))^x = lim x->inf (1-0)^x = 1 当k>0时,x->inf,0 < 2k/(x+k) < 1, lim x->inf ((x-k)/(x+k))^x = lim x->inf a^x (0inf (1+1/y)^(-2ky-k) = (其中...