如何让SmtpClient通过http代理服务器发送邮件
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发布时间：2022-04-30 00:56
共1个回答
热心网友
时间：2022-06-27 15:25
public static string
CreateTimeoutTestMessage(string server)
{
string Success =
"发送成功";
try
{
string _to = "1035092449@qq.com";
string _from =
"young-20@163.com";
string _subject = "Using the new SMTP client.";
string _body =
@"Using this new feature, you can send an e-mail
message from an application very easily.";
MailMessage message = new
MailMessage();
message.From = new
MailAddress(_from);
//可以利用MailMessage.To.Add方法增加要发送的邮件地址
message .To .Add (new MailAddress ("652105072@qq.com"));
message.To.Add(new
MailAddress(_to));
message.Subject = _subject;
message.Body = _body;
//添加附件
Attachment a = new
Attachment(@"C:/Users/Administrator/Desktop/smtpclient.rar");
message.Attachments.Add(a);
//设置邮箱的地址或IP
SmtpClient client = new
SmtpClient(server);
//设置邮箱端口，pop3端口:110, smtp端口是:25
client.Port = 25;
//设置超时时间
client.Timeout = 9999;
//要输入邮箱用户名与密码
client.Credentials = new NetworkCredential("young-20@163.com", "******");
client.Send(message);
}
catch (Exception ex)
{
Success = ex.ToString();
}
return Success;
}
[c-sharp] view
plaincopyprint?
public static string CreateTimeoutTestMessage(string server)
{
string Success = "发送成功";
try
{
string _to = "1035092449@qq.com";
string _from = "young-20@163.com";
string _subject = "Using the new SMTP client.";
string _body = @"Using this new feature, you can send an e-mail message from an application very easily.";
MailMessage message = new MailMessage();
message.From = new MailAddress(_from);
//可以利用MailMessage.To.Add方法增加要发送的邮件地址
message .To .Add (new MailAddress ("652105072@qq.com"));
message.To.Add(new MailAddress(_to));
message.Subject = _subject;
message.Body = _body;
//添加附件
Attachment a = new Attachment(@"C:/Users/Administrator/Desktop/smtpclient.rar");
message.Attachments.Add(a);
//设置邮箱的地址或IP
SmtpClient client = new SmtpClient(server);
//设置邮箱端口，pop3端口:110, smtp端口是:25
client.Port = 25;
//设置超时时间
client.Timeout = 9999;
//要输入邮箱用户名与密码
client.Credentials = new NetworkCredential("young-20@163.com", "******");
client.Send(message);
}
catch (Exception ex)
{
Success = ex.ToString();
}
return Success;
}
