一道数学题,

发布网友发布时间：2022-04-23 15:05

共4个回答

热心网友时间：2023-10-27 09:02

1.(fog)(2)=f(g(2))=f(3)=2
2.the question isn't clear, I guess you are asking f'og(2)
(f'og)(2)=f'(g(2))=f'(3)=7
3.(fog')(2)=f(g'(2))=f(4)=3
4.from(i), (fog)(2)=2, so the line pass though point (2,2)
the gradient of (fog) at (2,2)
=(fog)'(2)
=(f'og)(2)+(fog')(2) [chain rule]
=7+3 [from (ii) and (iii)
=10
so the gradient of the tangent to fog at (2,2) is -1/10

so the equation is y=(-1/10)x+b

substitude (2,2) in the equation

b=2+1/5=11/5

so the equation of the tangent to f o g at x = 2 is

y=(-1/10)x+11/5

热心网友时间：2023-10-27 09:02

看不清题,好像少了些数符

热心网友时间：2023-10-27 09:03

孔豆网问问专业老师！

热心网友时间：2023-10-27 09:03

sorry,l don`t know!

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