如何用C语言编一个密码生成器

发布网友发布时间：2022-04-23 00:13

共3个回答

热心网友时间：2023-07-02 19:02

C语言实现密码生成器，参考代码如下：

#include

#include
#include

//const char lower_chars[] = "abcdefghijklmnopqrstuvwxyz";
//const char upper_chars[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
//const char number_chars[] = "0123456789";
const char lower_chars[] = "abcdefghijkmnpqrstuvwxyz"; // no l or o
const char upper_chars[] = "ABCDEFGHJKLMNPQRSTUVWXYZ"; // no I or O
const char number_chars[] = "23456789"; // no 1 or 0
const char special_chars[] = "!@#$%^&*()-=_+[]{};:'\"<>,.?/";

const int _ks_pass_len = 17;

void mkpass(char pass[_ks_pass_len+1])
{
int i = 0, j = 0, k = 0,n = 0;
n = _ks_pass_len/4;
for (; i < n; i++)
{
pass[i] = lower_chars[rand()%(strlen(lower_chars))];
pass[i+n] = upper_chars[rand()%(strlen(upper_chars))];
pass[i+2*n] = number_chars[rand()%(strlen(number_chars))];
pass[i+3*n] = special_chars[rand()%(strlen(special_chars))];
}

j = _ks_pass_len - 4*n;
for (i = 0; i<j; i++) {
pass[i+4*n] = special_chars[rand()%(strlen(special_chars))];
}

//字符乱序
for (i = 0; i < 32; i++)
{
j = rand()%(_ks_pass_len);
k = pass[j];
pass[j] = pass[i%_ks_pass_len];
pass[i%_ks_pass_len] = k;
}

pass[_ks_pass_len] = '\0';
}

int _tmain(int argc, _TCHAR* argv[])
{
srand(time(0));
char szPass[_ks_pass_len+1];
for (int i=0; i<16; i++)
{
mkpass(szPass);
printf("%s\n",szPass);
}
return 0;
}<j; i++)

热心网友时间：2023-07-02 19:02

这个问题很好解决哦！先定义一个数组（16位），数组初始化为0，然后将你输入的字符存入数组！根据你输入的元素设计一个简单算法！输出结果就行啊！追问可是我对代码不专业，能不能帮忙写一下呢

热心网友时间：2023-07-02 19:03

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(void)
{
    int n; scanf("%d", &n);
    srand(n);
    printf("%03d%03d%03d", rand() % 1000, rand() % 1000, rand() % 1000);
    return 0;
}