MySQL 相同id取最新的数据?
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发布时间：2022-05-03 04:06
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时间：2022-05-03 08:27
.0.1
-- 服务器版本: 8.0.15 - MySQL Community Server - GPL
-- 服务器操作系统: Win64
-- HeidiSQL 版本: 9.5.0.5196
-- --------------------------------------------------------
/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET NAMES utf8 */;
/*!50503 SET NAMES utf8mb4 */;
/*!40014 SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0 */;
/*!40101 SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE=‘NO_AUTO_VALUE_ON_ZERO‘ */;
-- 导出 表 test.score 结构
CREATE TABLE IF NOT EXISTS `score` (
`score_id` bigint(20) NOT NULL AUTO_INCREMENT,
`student_name` varchar(32) DEFAULT NULL,
`course` varchar(30) DEFAULT NULL,
`score` int(11) DEFAULT NULL,
`create_time` datetime DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`score_id`)
) ENGINE=InnoDB AUTO_INCREMENT=10 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
-- 正在导出表 test.score 的数据：~8 rows (大约)
/*!40000 ALTER TABLE `score` DISABLE KEYS */;
INSERT INTO `score` (`score_id`, `student_name`, `course`, `score`, `create_time`) VALUES
(1, ‘张三‘, ‘语文‘, 66, ‘2019-07-24 10:35:05‘),
(2, ‘张三‘, ‘数学‘, 88, ‘2019-12-24 10:35:05‘),
(3, ‘张三‘, ‘英语‘, 92, ‘2019-02-24 10:35:05‘),
(4, ‘李四‘, ‘语文‘, 95, ‘2019-06-24 10:35:05‘),
(5, ‘李四‘, ‘数学‘, 55, ‘2019-08-24 10:35:05‘),
(6, ‘李四‘, ‘英语‘, 22, ‘2019-03-24 10:35:05‘),
(7, ‘王五‘, ‘语文‘, 99, ‘2019-06-23 10:35:05‘),
(8, ‘王五‘, ‘数学‘, 88, ‘2019-08-24 10:35:05‘),
(9, ‘王五‘, ‘英语‘, 77, ‘2019-05-24 10:35:05‘);
/*!40000 ALTER TABLE `score` ENABLE KEYS */;
/*!40101 SET SQL_MODE=IFNULL(@OLD_SQL_MODE, ‘‘) */;
/*!40014 SET FOREIGN_KEY_CHECKS=IF(@OLD_FOREIGN_KEY_CHECKS IS NULL, 1, @OLD_FOREIGN_KEY_CHECKS) */;
/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
执行sql
SELECT
*
FROM
(
SELECT DISTINCT
*
FROM
score
ORDER BY
create_time DESC
) s
GROUP BY
s.student_name;
结果展示
2 张三 数学 88 2019-12-24 10:35:05
5 李四 数学 55 2019-08-24 10:35:05
8 王五 数学 88 2019-08-24 10:35:05
mysql查询重复用户最新的一条数据
标签：英语 exist sel set core check com names mysql查询
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时间：2022-05-03 05:35
select * from 表 order by id desc limit 2
