发布网友 发布时间:2024-07-03 02:38
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热心网友 时间:2024-07-20 15:54
如图取坐标系H﹙000﹚,A﹙200﹚,B﹙020﹚,C1﹙00√5﹚
则A1﹙0,-2,0﹚B1﹙-2,0,0﹚,C﹙2,2,√5﹚
(Ⅰ)AC=﹛0,2,√5﹜,A1B1=﹛-2,2,0﹜,
cos﹤AC,A1B1﹥=AC•A1B1/﹙|AC||A1B1|﹚=√2/3
(Ⅱ)A1C1×AA1=﹛2√5,-2√5,4﹜.AA1C1法向量取n1=﹛√5,-√5,2﹜
A1C1×A1B1=﹛-2√5,-2√5,4﹜..A1C1B1法向量取n2=﹛-√5,-√5,2﹜
cos﹙二面角A-A1C1-B1﹚=2/7 ,二面角A-A1C1-B1的正弦值=3√5/7.
﹙Ⅲ﹚N﹙-1,0,√5/2﹚设M﹙x,y,0﹚ MN=﹛-1-x,-y,√5/2﹜
MN⊥A1C1B1 ∴MN=tn2 t=√5/4 x=1/4 y=5/4 BM=√10/4