java的分数运算问题

发布网友发布时间：2022-05-01 07:09

共2个回答

热心网友时间：2022-06-25 22:02

import java.util.Scanner;

public class Du{
public static void main(String args[]) throws Exception{

System.out.println("Please input a string in format xx/xx");

Scanner scanner = new Scanner(System.in);
String input = scanner.next();

String[] ary = input.split("/");

int numerator = Integer.parseInt(ary[0].trim());
int denominator = Integer.parseInt(ary[1].trim());

Fraction fra = new Fraction(numerator, denominator);
Fraction fra2 = new Fraction(15, 7);
Fraction fra3 = new Fraction(13, 12);

fra2.multiple(fra);//测试乘法
System.out.println("15/7 * 1/3 = " + fra2.toString());

fra.add(fra3);//测试加法
System.out.println("1/3 + 13/12 = " + fra.toString());
}
}

class Fraction{

private int numerator;//分子
private int denominator;//分母

public Fraction(int numerator, int denominator) throws Exception{
if(denominator == 0){//分母为0，出错
throw new Exception("Denominator can't be ZERO!");
}

this.numerator = numerator;
this.denominator = denominator;
}

public void multiple(Fraction fract2){//分数相乘
numerator *= fract2.numerator;//分子相乘
denominator *= fract2.denominator;//分母相乘

//结果约分
int lcd = getLCD(numerator, denominator);//最大公约数
numerator = numerator / lcd;
denominator = denominator /lcd;
}

public void add(Fraction fract2){
int gcm = getGCM(denominator, fract2.denominator);//最小公倍数作为分母

numerator *= gcm / denominator;//分子通分
fract2.numerator *= gcm / fract2.denominator;//第二个分子通分

numerator += fract2.numerator;//分子相加
denominator = gcm;//分母为最小公倍数

//约分
int lcd = getLCD(numerator, denominator);

if(lcd != 1){
numerator = numerator / lcd;
denominator = denominator / lcd;
}
}

public String toString(){
return numerator + "/" + denominator;
}

//求最大公约数
public static int getLCD(int num1, int num2){
int max = Math.max(num1, num2);
int min = Math.min(num1, num2);

while(max % min != 0){
int temp = max;
max = min;
min = temp % min;
}

return min;
}

//求最小公倍数
public static int getGCM(int num1, int num2){
return num1 * num2 /getLCD(num1, num2);
}

}
-----------------
Please input a string in format xx/xx
1/3
15/7 * 1/3 = 5/7
1/3 + 13/12 = 17/12

所有分数都可以通过乘10得倍数而达到分子和分母都是int类型的，所以没有问题的。

热心网友时间：2022-06-25 22:03

这个题目是否需要需要考虑精度问题？是否需要考虑分子分母为分整数？如果需要的话上面的答案是有问题的。需要换一下2个参数类型。涉及到小数的加减乘除最好是用BigDecimal类型然后再转换