...而且至少有一位数字是5的所有数字,输出格式一行一个

编写代码如下：include <stdio.h>#include <stdlib.h>int main(void){ int a,b,c,d,e,p,n; char str[5]; for(n=1;n<=9999;n++){if(n%7==0){ sprintf(str, "%0d", n); for(a=0;a<4;a++) { if(str[a]==53){ printf("得到目标数：%s\n"...

include <stdio.h>int main(void) {int i,t;for(i=7;i<9999;i+=7){for(t=i;t;t/=10){if(t%10==5){printf("%d\n",i);break;}}}return 0;}

} else if((a+b+c)%3 == 0 && (a == 5 || b == 5 || c == 5)) { printf("%d%d%d\n", a, b, c);} } } } return 1;}

int main(){ int i;for(i=1;i<=999;i++){ if(i%3==0&&((i%10==5)||(i/10)%10==5||(i/100)%10==5)) printf("%d\t",i);} } i%10==5)||(i/10)%10==5||(i/100)%10==5分别判断个位十位百位是否5

仅供参考：include "stdio.h"include "stdlib.h"include "string.h"void main(){ int i,n=0;char a[3];for(i=1;i<=999;i++)if(i%3==0){//判断可以被三整除 itoa(i,a,10);//将整型数据转换成字符串，便于查看各位是否含有5 for(int j=0;j 评论 0 0 0 加载更多 ...

245,252,259,315,350,357,385,455,504,511,518,525,532,539,546,553,560,567,574,581,588,595,651,658,665,735,756,805,854,875,945,952,959,1015,1050,1057,1085,1155,1225,1253,1295,1351,1358,1365,1435,1456,1505,1512,1519,1526,1533,1540,1547,1554,1561,1568,1575,1582,...

int main(void){ int i;int first ,second ,third;for(i=1;i<=999;i++){ if(i%3 == 0){ if(i/100){ first = i/100;second = (i%100)/10;third = i%10;if(first == 5 || second == 5 || third == 5)printf("%d ",i);}else if(i/10){ first = i/10;seco...

using namespace std;int main(int argc, char *argv[]){ int i;int a,b,c,d,s=0;for(i=1;i<=9999;i++){ if(i%7==0){a=i/1000;b=i/100%10;c=i/10%10;d=i%10;if(a==5||b==5||c==5||d==5){s++;if(s%5==0)cout<<endl;cout<<i<<" ";} } } system(...

代码如下：include<stdio.h> int main(){ int i=1,n=0,a,b,c;for(i=1;i<600;i++){ a=i/100;b=(i%100)/100;c=(i%100)%10;if(i%3==0&&(a==5||b==5||c==5)){ printf("%4d",i);n++;if(n%6==0)printf("\n");} } printf("\n%d",n);return 0;} ...

include <vector> void main(){ std::vector<int> Vint;int i,j;for(i=0;i<999;i++)if (i%3==0)Vint.push_back(i);for (i=0;i<Vint.size();i++){ j=Vint[i];while(j!=0){ if (j%5==0 && j%10!=0){ printf("%d \t",Vint[i]);break;} j=j/10;} } } ...