关于运算符重载函数？？先看下面的这个程序，说的就是复数和实数相加，是正确的。

发布网友 发布时间：2022-04-26 19:10

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共3个回答

热心网友 时间：2023-10-22 21:14

谭浩强版的书上的例子很多都是错误的！他在写书的时候是想当然的，没有上机实践过！以后你还会遇到很多的，只要错，该就行了！“尽信书，不如无书！”也算是个经验教训吧！编译器是很少出错的！！

改正后的程序如下：
#include <iostream.h>
class Complex
{public:
Complex(){real=0;imag=0;}
Complex(double r){real=r;imag=0;}
Complex(double r,double i){real=r;imag=i;}
friend Complex operator + (Complex &c1,Complex &c2); //这是类的对象的调用实现函数的；下面同此！

void display();
private:
double real;
double imag;
};

Complex operator + (Complex &c1,Complex &c2)
{return Complex(c1.real+c2.real, c1.imag+c2.imag);}

void Complex::display()
{cout<<"("<<real<<"+"<<imag<<"i)"<<endl;}

int main()
{Complex c1(3,4),c2(5,-10),c3;
c3=c1+c3; #include <iostream.h>
class Complex
{public:
Complex(){real=0;imag=0;}
Complex(double r){real=r;imag=0;}
Complex(double r,double i){real=r;imag=i;}
friend Complex operator + (Complex &c1,Complex &c2);
void display();
private:
double real;
double imag;
};

Complex operator + (Complex &c1,Complex &c2)
{return Complex(c1.real+c2.real, c1.imag+c2.imag);}

void Complex::display()
{cout<<"("<<real<<"+"<<imag<<"i)"<<endl;}

int main()
{Complex c1(3,4),c2(5,-10),c3;
c3=c1+c3; //2.5不是对象，不能被重载函数调用
c3.display();
return 0;
}
c3.display();
return 0;
}

热心网友 时间：2023-10-22 21:14

能改的

#include <iostream.h>
class Complex
{public:
Complex(){real=0;imag=0;}
Complex(double r){real=r;imag=0;}
Complex(double r,double i){real=r;imag=i;}
friend Complex operator + (Complex &c1,Complex &c2); //
void display();
private:
double real;
double imag;
};

Complex operator + (Complex &c1,Complex &c2) //上下都要改的
{return Complex(c1.real+c2.real, c1.imag+c2.imag);}

void Complex::display()
{cout<<"("<<real<<"+"<<imag<<"i)"<<endl;}

int main()
{Complex c1(3,4),c2(5,-10),c3;
c3=c1+c3; //2.5并不是类，会让&c2出错
c3.display();
return 0;
}

热心网友 时间：2023-10-22 21:15

去看看引用型参和非引用型参的区别。