用python编程求多项式sn=1-3+5-7+9-11+……的前100项和

发布网友发布时间：2022-04-26 21:54

共3个回答

热心网友时间：2023-11-07 14:14

he = 0
for n in range(0,100):
    if (n % 2 == 0):
        he += 2 * n +1
    else:
        he -= 2 * n + 1

print(he)

代码这样就差不多了

热心网友时间：2023-11-07 14:14

t,a,r=0,1,0
while a<=100:
空if t==0:
空空r,t=r+a,1
空else:
空空r,t=r-a,0
空a+=2
print r

热心网友时间：2023-11-07 14:15

sum = 0
for i in range(1,101):
if (i % 2 == 0):
sum -= 2 * i -1
else:
sum += 2 * i - 1

print(sum)

热心网友时间：2023-11-07 14:14

he = 0
for n in range(0,100):
    if (n % 2 == 0):
        he += 2 * n +1
    else:
        he -= 2 * n + 1

print(he)

代码这样就差不多了

热心网友时间：2023-11-07 14:14

t,a,r=0,1,0
while a<=100:
空if t==0:
空空r,t=r+a,1
空else:
空空r,t=r-a,0
空a+=2
print r

热心网友时间：2023-11-07 14:15

sum = 0
for i in range(1,101):
if (i % 2 == 0):
sum -= 2 * i -1
else:
sum += 2 * i - 1

print(sum)