发布网友 发布时间:2022-05-23 10:31
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热心网友 时间:2023-10-20 13:11
设A(x1,y1,z1),B(x2,y2,z2),C(x3,y3,z3)则属于平面内的向量AB(x2-x1,y2-y1,z2-z1), AC(x3-x1,y3-y1,z3-z1)则平面方程为| x y z | |x2-x1 y2-y1 z2-z1|=0 |x3-x1 y3-y1 z3-z1|有:x[(y2-y1)(z3-z1)-(z2-z1)(y3-y1)]-y[(x2-x1)(z3-z1)-(z2-z1)(x3-x1)]+z[(x2-x1)(y3-y1)-(y2-y1)(x3-x1)]=0