发布网友 发布时间:2024-10-22 04:18
共2个回答
热心网友 时间:2024-10-23 01:29
cos2x-2sinx-1=cos2x-1-2sinx=-2sin�0�5x-2sinx=-2(sin�0�5x+sinx)=-2(sin�0�5x+sinx+1/4-1/4)=-2(sinx+1/2)�0�5+1/2,所以最大值为1/2热心网友 时间:2024-10-23 01:32
f(x)=cos2x-2sinx-1=-2[(sinx)^2+sinx]热心网友 时间:2024-10-23 01:26
cos2x-2sinx-1=cos2x-1-2sinx=-2sin�0�5x-2sinx=-2(sin�0�5x+sinx)=-2(sin�0�5x+sinx+1/4-1/4)=-2(sinx+1/2)�0�5+1/2,所以最大值为1/2热心网友 时间:2024-10-23 01:25
f(x)=cos2x-2sinx-1=-2[(sinx)^2+sinx]