数据结构生成树问题

发布网友发布时间：2022-04-22 04:56

共1个回答

热心网友时间：2023-06-24 02:12

/* 用邻接矩阵表示的图的prim算法的源程序*/

#include<stdio.h>
#define MAXVEX 6

typedef char VexType;

typedef float AdjType;

typedef struct {
int n; /* 图的顶点个数 */
/*VexType vexs[MAXVEX]; 顶点信息 */
AdjType arcs[MAXVEX][MAXVEX]; /* 边信息 */
} GraphMatrix;

typedef struct{
int start_vex, stop_vex; /* 边的起点和终点 */
AdjType weight; /* 边的权 */
} Edge;

Edge mst[5];

#define MAX 1e+8

void prim(GraphMatrix * pgraph, Edge mst[]) {
int i, j, min, vx, vy;
float weight, minweight; Edge edge;

for (i = 0; i < pgraph->n-1; i++) {
mst[i].start_vex = 0;
mst[i].stop_vex = i+1;
mst[i].weight = pgraph->arcs[0][i+1];
}

for (i = 0; i < pgraph->n-1; i++) { /* 共n-1条边 */
minweight = MAX; min = i;
for (j = i; j < pgraph->n-1; j++)/* 从所有边(vx,vy)(vx∈U,vy∈V-U)中选出最短的边 */
if(mst[j].weight < minweight) {
minweight = mst[j].weight;
min = j;
}

/* mst[min]是最短的边(vx,vy)(vx∈U, vy∈V-U)，将mst[min]加入最小生成树 */
edge = mst[min];
mst[min] = mst[i];
mst[i] = edge;
vx = mst[i].stop_vex; /* vx为刚加入最小生成树的顶点的下标 */

for(j = i+1; j < pgraph->n-1; j++) { /* 调整mst[i+1]到mst[n-1] */
vy=mst[j].stop_vex; weight = pgraph->arcs[vx][vy];
if (weight < mst[j].weight) {
mst[j].weight = weight;
mst[j].start_vex = vx;
}
}
}
}

GraphMatrix graph = {
6,
,
,
,
,
,

}
};

int main(){
int i;
prim(&graph,mst);
for (i = 0; i < graph.n-1; i++)
printf("(%d %d %.0f)\n", mst[i].start_vex,
mst[i].stop_vex, mst[i].weight);
return 0;
}
追问谢谢，但是我问的不是有权值的生成树