谁有语音端点检测算法程序?如何在matlab中运行?
发布网友
发布时间:2022-05-29 22:43
我来回答
共2个回答
热心网友
时间:2024-10-14 08:28
基于Matlab编写的语音端点检测程序
function [x1,x2] = vad(x)
%幅度归一化到[-1,1]
x = double(x);
x = x / max(abs(x));
%常数设置
FrameLen = 240;
FrameInc = 80;
amp1 = 10;
amp2 = 2;
zcr1 = 10;
zcr2 = 5;
maxsilence = 8; % 6*10ms = 30ms
minlen = 15; % 15*10ms = 150ms
status = 0;
count = 0;
silence = 0;
%计算过零率
tmp1 = enframe(x(1:end-1), FrameLen, FrameInc);
tmp2 = enframe(x(2:end) , FrameLen, FrameInc);
signs = (tmp1.*tmp2)<0;
diffs = (tmp1 -tmp2)>0.02;
zcr = sum(signs.*diffs, 2);
%计算短时能量
amp = sum(abs(enframe(filter([1 -0.9375], 1, x), FrameLen, FrameInc)), 2);
%调整能量门限
amp1 = min(amp1, max(amp)/4);
amp2 = min(amp2, max(amp)/8);
%开始端点检测
x1 = 0;
x2 = 0;
for n=1:length(zcr)
goto = 0;
switch status
case {0,1}
% 0 = 静音,
1 = 可能开始
if amp(n) > amp1
% 确信进入语音段
x1 = max(n-count-1,1);
status = 2;
silence = 0;
count = count + 1;
elseif amp(n) > amp2 | ... % 可能处于语音段
zcr(n) > zcr2
status = 1;
count = count + 1;
else
% 静音状态
status = 0;
count = 0;
end
case 2,
% 2 = 语音段
if amp(n) > amp2 | ... % 保持在语音段
zcr(n) > zcr2
count = count + 1;
else
% 语音将结束
silence = silence+1;
if silence < maxsilence % 静音还不够长,尚未结束
count = count + 1;
elseif count < minlen % 语音长度太短,认为是噪声
status = 0;
silence = 0;
count = 0;
else
% 语音结束
status = 3;
end
end
case 3,
break;
end
end
count = count-silence/2;
x2 = x1 + count -1;
subplot(311)
plot(x)
axis([1 length(x) -1 1])
ylabel('Speech');
line([x1*FrameInc x1*FrameInc], [-1 1], 'Color', 'red');
line([x2*FrameInc x2*FrameInc], [-1 1], 'Color', 'red');
subplot(312)
plot(amp);
axis([1 length(amp) 0 max(amp)])
ylabel('Energy');
line([x1 x1], [min(amp),max(amp)], 'Color', 'red');
line([x2 x2], [min(amp),max(amp)], 'Color', 'red');
subplot(313)
plot(zcr);
axis([1 length(zcr) 0 max(zcr)])
ylabel('ZCR');
line([x1 x1], [min(zcr),max(zcr)], 'Color', 'red');line([x2 x2], [min(zcr),max(zcr)], 'Color', 'red');
热心网友
时间:2024-10-14 08:29
The abstract pronunciation signal vertex examination is the digitalpronunciation signal processing foundation link. But pronunciationsignal because has each