PHP怎么查看有几个二维数组

//你的数组少写了个逗号$data = array(array("price" => "6874","air" => "国泰"),array("price" => "4726","air" => "大韩航空"),array("price" => "6569","air" => "国泰航空"),array("price" => "6569","air" => "卡塔尔航空"),array("price" => "3380","air" ...

可以使用遍历二维数组的办法判断，还可以统计出现的次数或者输出key值。代码如下：<?php$d=100;$tot=0;$cars=array(array("Volvo",100,96),array("BMW",100,59),array("Toyota",110,100));foreach($cars as $v){if(is_array($v)){foreach($v as $a){if($a==$d)$tot++;}}else...

回答：这个二维数组是规律性的吧n*2+1位置上的元素合并到第n*2个元素里面吗? 而且,干嘛一定要用foreach呢,考验算法技巧吗?

控制层functiontest_func(){//获取model页面需要的两个参数$competition_id=$_GET["competition_id"];$report_class=$_GET["report_class"];$this->load->model("Action");//引入model$data["head"]=$this->Action->get_report_item($competition_id,$report_class);//引用model的函数$this-...

array('a'=>'1','b'=>'2','c'=>'5','d'=>'56'),array('a'=>'1','c'=>'5','d'=>'56'),array('a'=>'1','c'=>'5','e'=>'44'),array('a'=>'1','c'=>'5','d'=>'56','f'=>'d'));if (count($arr)>0){ foreach($arr as $key=>$val){ if...

方法是使用array_udiff函数。代码如下：function diff_arr($a, $b){ return $a["id"] > $b["id"] ? 1 : ($a["id"] < $b["id"] ? -1 : 0);} print_r(array_udiff($arr0, $arr1, "diff_arr"));

//2维 [x][y]x=22;y=11;a=array_fill(0,$x,array_fill(0,$y,array()));//$a 就是 [22][11]的2维数组

=> 22) , array('name' => 'mm', 'age' => 26) , array('name' => 'lili', 'age' => 25));//五个同学的二维数组信息foreach($users as $k=>$v){ if($k == x){ ...//PHP处理代码，按照下标$k进行简单查询，x为数字 } if($v[...

arr=array(array(3,2),array(8,56),);var_dump($arr[1][1]);//输出：56

首先你这个php的二维写的有问题，应该是这样的 <?php $arr=Array ( 96 => Array ( 'id' => 96, 's1' => 1,'s2' => 1, 'sel1' => 22.80, 'sel2' => 16.8, 'name' => '张三', 'dat' => 2014-11-25 ), '64a' => Array( 'id' => 64, 's1' => 1...